b^2=-2+3b

Solution for b^2=-2+3b equation:

Simplifying
b2 = -2 + 3b

Solving
b2 = -2 + 3b

Solving for variable 'b'.

Reorder the terms:
2 + -3b + b2 = -2 + 3b + 2 + -3b

Reorder the terms:
2 + -3b + b2 = -2 + 2 + 3b + -3b

Combine like terms: -2 + 2 = 0
2 + -3b + b2 = 0 + 3b + -3b
2 + -3b + b2 = 3b + -3b

Combine like terms: 3b + -3b = 0
2 + -3b + b2 = 0

Factor a trinomial.
(1 + -1b)(2 + -1b) = 0

Subproblem 1
Set the factor '(1 + -1b)' equal to zero and attempt to solve:

Simplifying
1 + -1b = 0

Solving
1 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1b = 0 + -1
-1b = 0 + -1

Combine like terms: 0 + -1 = -1
-1b = -1

Divide each side by '-1'.
b = 1

Simplifying
b = 1
Subproblem 2
Set the factor '(2 + -1b)' equal to zero and attempt to solve:

Simplifying
2 + -1b = 0

Solving
2 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1b = 0 + -2
-1b = 0 + -2

Combine like terms: 0 + -2 = -2
-1b = -2

Divide each side by '-1'.
b = 2

Simplifying
b = 2
Solution
b = {1, 2}